Base | Representation |
---|---|
bin | 10100101010101010100… |
… | …001111111000010010111 |
3 | 12000202210012022110222000 |
4 | 110222222201333002113 |
5 | 141232032230241401 |
6 | 3004233032010343 |
7 | 204414612613551 |
oct | 24525241770227 |
9 | 5022705273860 |
10 | 1420200243351 |
11 | 4a833801608a |
12 | 1ab2b22309b3 |
13 | a3c029227a6 |
14 | 4ca493384d1 |
15 | 26e21782186 |
hex | 14aaa87f097 |
1420200243351 has 64 divisors (see below), whose sum is σ = 2220906508800. Its totient is φ = 894473342208.
The previous prime is 1420200243347. The next prime is 1420200243373. The reversal of 1420200243351 is 1533420020241.
1420200243351 is a `hidden beast` number, since 1 + 4 + 20 + 200 + 2 + 433 + 5 + 1 = 666.
It is not a de Polignac number, because 1420200243351 - 22 = 1420200243347 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420200243151) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 573353725 + ... + 573356201.
It is an arithmetic number, because the mean of its divisors is an integer number (34701664200).
Almost surely, 21420200243351 is an apocalyptic number.
1420200243351 is a deficient number, since it is larger than the sum of its proper divisors (800706265449).
1420200243351 is a wasteful number, since it uses less digits than its factorization.
1420200243351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5165 (or 5159 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 1420200243351 its reverse (1533420020241), we get a palindrome (2953620263592).
The spelling of 1420200243351 in words is "one trillion, four hundred twenty billion, two hundred million, two hundred forty-three thousand, three hundred fifty-one".
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