Base | Representation |
---|---|
bin | 10100101010101010100… |
… | …101010110001001000111 |
3 | 12000202210020222020120022 |
4 | 110222222211112021013 |
5 | 141232032441440143 |
6 | 3004233102525355 |
7 | 204414623243354 |
oct | 24525245261107 |
9 | 5022706866508 |
10 | 1420201124423 |
11 | 4a8338568044 |
12 | 1ab2b259685b |
13 | a3c02b70833 |
14 | 4ca494c762b |
15 | 26e218a8268 |
hex | 14aaa956247 |
1420201124423 has 2 divisors, whose sum is σ = 1420201124424. Its totient is φ = 1420201124422.
The previous prime is 1420201124357. The next prime is 1420201124431. The reversal of 1420201124423 is 3244211020241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1420201124423 - 230 = 1419127382599 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1420201124392 and 1420201124401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420201124473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710100562211 + 710100562212.
It is an arithmetic number, because the mean of its divisors is an integer number (710100562212).
Almost surely, 21420201124423 is an apocalyptic number.
1420201124423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420201124423 is an equidigital number, since it uses as much as digits as its factorization.
1420201124423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3072, while the sum is 26.
Adding to 1420201124423 its reverse (3244211020241), we get a palindrome (4664412144664).
The spelling of 1420201124423 in words is "one trillion, four hundred twenty billion, two hundred one million, one hundred twenty-four thousand, four hundred twenty-three".
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