Base | Representation |
---|---|
bin | 10100101010101010100… |
… | …101010110001001001111 |
3 | 12000202210020222020120121 |
4 | 110222222211112021033 |
5 | 141232032441440211 |
6 | 3004233102525411 |
7 | 204414623243365 |
oct | 24525245261117 |
9 | 5022706866517 |
10 | 1420201124431 |
11 | 4a8338568051 |
12 | 1ab2b2596867 |
13 | a3c02b7083b |
14 | 4ca494c7635 |
15 | 26e218a8271 |
hex | 14aaa95624f |
1420201124431 has 2 divisors, whose sum is σ = 1420201124432. Its totient is φ = 1420201124430.
The previous prime is 1420201124423. The next prime is 1420201124473. The reversal of 1420201124431 is 1344211020241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1420201124431 - 23 = 1420201124423 is a prime.
It is a super-2 number, since 2×14202011244312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1420201124396 and 1420201124405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420201124491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710100562215 + 710100562216.
It is an arithmetic number, because the mean of its divisors is an integer number (710100562216).
Almost surely, 21420201124431 is an apocalyptic number.
1420201124431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420201124431 is an equidigital number, since it uses as much as digits as its factorization.
1420201124431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1420201124431 its reverse (1344211020241), we get a palindrome (2764412144672).
The spelling of 1420201124431 in words is "one trillion, four hundred twenty billion, two hundred one million, one hundred twenty-four thousand, four hundred thirty-one".
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