14202050402327 has 2 divisors, whose sum is σ = 14202050402328. Its totient is φ = 14202050402326.

The previous prime is 14202050402237. The next prime is 14202050402329. The reversal of 14202050402327 is 72320405020241.

14202050402327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (14202050402237) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14202050402327 - 2¹⁸ = 14202050140183 is a prime.

Together with 14202050402329, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14202050402293 and 14202050402302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14202050402329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101025201163 + 7101025201164.

It is an arithmetic number, because the mean of its divisors is an integer number (7101025201164).

Almost surely, 2^{14202050402327} is an apocalyptic number.

14202050402327 is a deficient number, since it is larger than the sum of its proper divisors (1).

14202050402327 is an equidigital number, since it uses as much as digits as its factorization.

14202050402327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 32.

Adding to 14202050402327 its reverse (72320405020241), we get a palindrome (86522455422568).

The spelling of 14202050402327 in words is "fourteen trillion, two hundred two billion, fifty million, four hundred two thousand, three hundred twenty-seven".