Base | Representation |
---|---|
bin | 1100111010101011101110… |
… | …1110001010001000101000 |
3 | 1212021201122111100212101020 |
4 | 3032222323232022020220 |
5 | 3330142313144220404 |
6 | 50112241324452440 |
7 | 2664040341244125 |
oct | 316527356121050 |
9 | 55251574325336 |
10 | 14202311320104 |
11 | 4586191539896 |
12 | 17146053aa120 |
13 | 7c037007c94b |
14 | 3715774c774c |
15 | 19967c22ced9 |
hex | ceabbb8a228 |
14202311320104 has 128 divisors (see below), whose sum is σ = 35706769920000. Its totient is φ = 4707398608640.
The previous prime is 14202311320049. The next prime is 14202311320117. The reversal of 14202311320104 is 40102311320241.
14202311320104 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9474523147 + ... + 9474524645.
It is an arithmetic number, because the mean of its divisors is an integer number (278959140000).
Almost surely, 214202311320104 is an apocalyptic number.
It is an amenable number.
14202311320104 is an abundant number, since it is smaller than the sum of its proper divisors (21504458599896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14202311320104 is a wasteful number, since it uses less digits than its factorization.
14202311320104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4103 (or 4099 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 14202311320104 its reverse (40102311320241), we get a palindrome (54304622640345).
The spelling of 14202311320104 in words is "fourteen trillion, two hundred two billion, three hundred eleven million, three hundred twenty thousand, one hundred four".
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