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14202311320117 is a prime number
BaseRepresentation
bin1100111010101011101110…
…1110001010001000110101
31212021201122111100212101201
43032222323232022020311
53330142313144220432
650112241324452501
72664040341244144
oct316527356121065
955251574325351
1014202311320117
1145861915398a8
1217146053aa131
137c037007c95b
143715774c775b
1519967c22cee7
hexceabbb8a235

14202311320117 has 2 divisors, whose sum is σ = 14202311320118. Its totient is φ = 14202311320116.

The previous prime is 14202311320049. The next prime is 14202311320151. The reversal of 14202311320117 is 71102311320241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13653276261156 + 549035058961 = 3695034^2 + 740969^2 .

It is a cyclic number.

It is not a de Polignac number, because 14202311320117 - 215 = 14202311287349 is a prime.

It is a super-3 number, since 3×142023113201173 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14202311320187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101155660058 + 7101155660059.

It is an arithmetic number, because the mean of its divisors is an integer number (7101155660059).

Almost surely, 214202311320117 is an apocalyptic number.

It is an amenable number.

14202311320117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14202311320117 is an equidigital number, since it uses as much as digits as its factorization.

14202311320117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 14202311320117 its reverse (71102311320241), we get a palindrome (85304622640358).

The spelling of 14202311320117 in words is "fourteen trillion, two hundred two billion, three hundred eleven million, three hundred twenty thousand, one hundred seventeen".