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1420236406433 = 13109248954341
BaseRepresentation
bin10100101010101100101…
…011111011111010100001
312000202212201100202101102
4110222230223323322201
5141232121010001213
63004240403044145
7204415532161355
oct24525453737241
95022781322342
101420236406433
114a8356475a29
121ab302370655
13a3c0a274a70
144ca5006d465
1526e24a27158
hex14aacafbea1

1420236406433 has 4 divisors (see below), whose sum is σ = 1529485360788. Its totient is φ = 1310987452080.

The previous prime is 1420236406427. The next prime is 1420236406439. The reversal of 1420236406433 is 3346046320241.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1420236406427) and next prime (1420236406439).

It can be written as a sum of positive squares in 2 ways, for example, as 509257786129 + 910978620304 = 713623^2 + 954452^2 .

It is a cyclic number.

It is not a de Polignac number, because 1420236406433 - 210 = 1420236405409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1420236406439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54624477158 + ... + 54624477183.

It is an arithmetic number, because the mean of its divisors is an integer number (382371340197).

Almost surely, 21420236406433 is an apocalyptic number.

1420236406433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1420236406433 is a deficient number, since it is larger than the sum of its proper divisors (109248954355).

1420236406433 is a wasteful number, since it uses less digits than its factorization.

1420236406433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109248954354.

The product of its (nonzero) digits is 248832, while the sum is 38.

It can be divided in two parts, 142023 and 6406433, that added together give a palindrome (6548456).

The spelling of 1420236406433 in words is "one trillion, four hundred twenty billion, two hundred thirty-six million, four hundred six thousand, four hundred thirty-three".

Divisors: 1 13 109248954341 1420236406433