Base | Representation |
---|---|
bin | 1100111010101110101101… |
… | …0110111111100111110111 |
3 | 1212021210201012021011022110 |
4 | 3032223223112333213313 |
5 | 3330200432300212403 |
6 | 50112452515102103 |
7 | 2664066214520322 |
oct | 316535326774767 |
9 | 55253635234273 |
10 | 14203110554103 |
11 | 45865616a7159 |
12 | 17147a8ba1933 |
13 | 7c0469824c83 |
14 | 3716116d37b9 |
15 | 1996c74a3103 |
hex | ceaeb5bf9f7 |
14203110554103 has 8 divisors (see below), whose sum is σ = 18937689273216. Its totient is φ = 9468636102200.
The previous prime is 14203110554093. The next prime is 14203110554137. The reversal of 14203110554103 is 30145501130241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14203110554103 - 212 = 14203110550007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14203110554173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25748403 + ... + 26294228.
It is an arithmetic number, because the mean of its divisors is an integer number (2367211159152).
Almost surely, 214203110554103 is an apocalyptic number.
14203110554103 is a deficient number, since it is larger than the sum of its proper divisors (4734578719113).
14203110554103 is an equidigital number, since it uses as much as digits as its factorization.
14203110554103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52133605.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 14203110554103 its reverse (30145501130241), we get a palindrome (44348611684344).
The spelling of 14203110554103 in words is "fourteen trillion, two hundred three billion, one hundred ten million, five hundred fifty-four thousand, one hundred three".
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