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1420315687247 is a prime number
BaseRepresentation
bin10100101010110001011…
…010010111100101001111
312000210002020112122012212
4110222301122113211033
5141232301303442442
63004252314221035
7204420514100642
oct24526132274517
95023066478185
101420315687247
114a83971a5866
121ab324a2477b
13a3c208129a2
144ca5a7c9a59
1526e2b987a82
hex14ab169794f

1420315687247 has 2 divisors, whose sum is σ = 1420315687248. Its totient is φ = 1420315687246.

The previous prime is 1420315687157. The next prime is 1420315687249. The reversal of 1420315687247 is 7427865130241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1420315687247 - 224 = 1420298910031 is a prime.

Together with 1420315687249, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1420315687195 and 1420315687204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1420315687249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710157843623 + 710157843624.

It is an arithmetic number, because the mean of its divisors is an integer number (710157843624).

Almost surely, 21420315687247 is an apocalyptic number.

1420315687247 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420315687247 is an equidigital number, since it uses as much as digits as its factorization.

1420315687247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2257920, while the sum is 50.

The spelling of 1420315687247 in words is "one trillion, four hundred twenty billion, three hundred fifteen million, six hundred eighty-seven thousand, two hundred forty-seven".