14204025145141 has 4 divisors (see below), whose sum is σ = 15296642464012. Its totient is φ = 13111407826272.

The previous prime is 14204025145103. The next prime is 14204025145183. The reversal of 14204025145141 is 14154152040241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8624083549041 + 5579941596100 = 2936679^2 + 2362190^2 .

It is a cyclic number.

It is not a de Polignac number, because 14204025145141 - 2¹³ = 14204025136949 is a prime.

It is a super-2 number, since 2×14204025145141² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14204025145097 and 14204025145106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14204025145441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546308659416 + ... + 546308659441.

It is an arithmetic number, because the mean of its divisors is an integer number (3824160616003).

Almost surely, 2^{14204025145141} is an apocalyptic number.

It is an amenable number.

14204025145141 is a deficient number, since it is larger than the sum of its proper divisors (1092617318871).

14204025145141 is a wasteful number, since it uses less digits than its factorization.

14204025145141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1092617318870.

The product of its (nonzero) digits is 25600, while the sum is 34.

Adding to 14204025145141 its reverse (14154152040241), we get a palindrome (28358177185382).

The spelling of 14204025145141 in words is "fourteen trillion, two hundred four billion, twenty-five million, one hundred forty-five thousand, one hundred forty-one".