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14204125121 is a prime number
BaseRepresentation
bin11010011101010000…
…11011111111000001
31100122220120022121012
431032220123333001
5213042224000441
610305243410305
71011664033334
oct151650337701
940586508535
1014204125121
11602994948a
122904b23995
1314549ab984
1498a65061b
155820049eb
hex34ea1bfc1

14204125121 has 2 divisors, whose sum is σ = 14204125122. Its totient is φ = 14204125120.

The previous prime is 14204125099. The next prime is 14204125193. The reversal of 14204125121 is 12152140241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8168544400 + 6035580721 = 90380^2 + 77689^2 .

It is an emirp because it is prime and its reverse (12152140241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14204125121 - 218 = 14203862977 is a prime.

It is not a weakly prime, because it can be changed into another prime (14209125121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102062560 + 7102062561.

It is an arithmetic number, because the mean of its divisors is an integer number (7102062561).

Almost surely, 214204125121 is an apocalyptic number.

It is an amenable number.

14204125121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204125121 is an equidigital number, since it uses as much as digits as its factorization.

14204125121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 640, while the sum is 23.

Adding to 14204125121 its reverse (12152140241), we get a palindrome (26356265362).

The spelling of 14204125121 in words is "fourteen billion, two hundred four million, one hundred twenty-five thousand, one hundred twenty-one".