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14204445141 = 34734815047
BaseRepresentation
bin11010011101010011…
…01010000111010101
31100122221011120120210
431032221222013111
5213042314221031
610305254320033
71011666535335
oct151651520725
940587146523
1014204445141
11602a047967
122905059019
131454a91533
1498a6d50c5
15582069746
hex34ea6a1d5

14204445141 has 4 divisors (see below), whose sum is σ = 18939260192. Its totient is φ = 9469630092.

The previous prime is 14204445131. The next prime is 14204445169. The reversal of 14204445141 is 14154440241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14204445141 - 25 = 14204445109 is a prime.

It is a super-3 number, since 3×142044451413 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14204445099 and 14204445108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14204445131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2367407521 + ... + 2367407526.

It is an arithmetic number, because the mean of its divisors is an integer number (4734815048).

Almost surely, 214204445141 is an apocalyptic number.

It is an amenable number.

14204445141 is a deficient number, since it is larger than the sum of its proper divisors (4734815051).

14204445141 is an equidigital number, since it uses as much as digits as its factorization.

14204445141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4734815050.

The product of its (nonzero) digits is 10240, while the sum is 30.

Adding to 14204445141 its reverse (14154440241), we get a palindrome (28358885382).

The spelling of 14204445141 in words is "fourteen billion, two hundred four million, four hundred forty-five thousand, one hundred forty-one".

Divisors: 1 3 4734815047 14204445141