Base | Representation |
---|---|
bin | 11010011101011011… |
… | …01110110100010111 |
3 | 1100200000011211101111 |
4 | 31032231232310113 |
5 | 213043102403413 |
6 | 10305333235451 |
7 | 1012011603514 |
oct | 151655566427 |
9 | 40600154344 |
10 | 14205512983 |
11 | 602a707182 |
12 | 2905492b87 |
13 | 14550765ac |
14 | 98a8d230b |
15 | 5821cad3d |
hex | 34eb6ed17 |
14205512983 has 2 divisors, whose sum is σ = 14205512984. Its totient is φ = 14205512982.
The previous prime is 14205512947. The next prime is 14205512989. The reversal of 14205512983 is 38921550241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14205512983 is a prime.
It is a super-2 number, since 2×142055129832 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14205512989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102756491 + 7102756492.
It is an arithmetic number, because the mean of its divisors is an integer number (7102756492).
Almost surely, 214205512983 is an apocalyptic number.
14205512983 is a deficient number, since it is larger than the sum of its proper divisors (1).
14205512983 is an equidigital number, since it uses as much as digits as its factorization.
14205512983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 14205512983 in words is "fourteen billion, two hundred five million, five hundred twelve thousand, nine hundred eighty-three".
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