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142055520515383 is a prime number
BaseRepresentation
bin100000010011001011100000…
…110101101011010100110111
3200121222101010110201210121211
4200103023200311223110313
5122104414201222443013
61222043223305222251
741631113140264666
oct4023134065532467
9617871113653554
10142055520515383
1141299453a50a92
1213b2338a491987
136135a1665c327
142711749744ddd
1511652cb83223d
hex8132e0d6b537

142055520515383 has 2 divisors, whose sum is σ = 142055520515384. Its totient is φ = 142055520515382.

The previous prime is 142055520515333. The next prime is 142055520515399. The reversal of 142055520515383 is 383515025550241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142055520515383 is a prime.

It is a super-3 number, since 3×1420555205153833 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142055520515323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71027760257691 + 71027760257692.

It is an arithmetic number, because the mean of its divisors is an integer number (71027760257692).

Almost surely, 2142055520515383 is an apocalyptic number.

142055520515383 is a deficient number, since it is larger than the sum of its proper divisors (1).

142055520515383 is an equidigital number, since it uses as much as digits as its factorization.

142055520515383 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600000, while the sum is 49.

The spelling of 142055520515383 in words is "one hundred forty-two trillion, fifty-five billion, five hundred twenty million, five hundred fifteen thousand, three hundred eighty-three".