Base | Representation |
---|---|
bin | 10100101011010101010… |
… | …011011111011110001111 |
3 | 12000211122012122101212222 |
4 | 110223111103133132033 |
5 | 141240014433124320 |
6 | 3004432145045555 |
7 | 204441445365164 |
oct | 24532523373617 |
9 | 5024565571788 |
10 | 1420917864335 |
11 | 4a8676100382 |
12 | 1ab4726268bb |
13 | a3cb84c14a8 |
14 | 4cab677c06b |
15 | 26e64785825 |
hex | 14ad54df78f |
1420917864335 has 4 divisors (see below), whose sum is σ = 1705101437208. Its totient is φ = 1136734291464.
The previous prime is 1420917864329. The next prime is 1420917864337. The reversal of 1420917864335 is 5334687190241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1420917864335 - 230 = 1419844122511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420917864337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142091786429 + ... + 142091786438.
It is an arithmetic number, because the mean of its divisors is an integer number (426275359302).
It is a 1-persistent number, because it is pandigital, but 2⋅1420917864335 = 2841835728670 is not.
Almost surely, 21420917864335 is an apocalyptic number.
1420917864335 is a deficient number, since it is larger than the sum of its proper divisors (284183572873).
1420917864335 is an equidigital number, since it uses as much as digits as its factorization.
1420917864335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 284183572872.
The product of its (nonzero) digits is 4354560, while the sum is 53.
The spelling of 1420917864335 in words is "one trillion, four hundred twenty billion, nine hundred seventeen million, eight hundred sixty-four thousand, three hundred thirty-five".
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