Base | Representation |
---|---|
bin | 1100111011001000011000… |
… | …1001110101111110111011 |
3 | 1212022110111111202110001211 |
4 | 3032302012021311332323 |
5 | 3330304041122330043 |
6 | 50115552434223551 |
7 | 2664432052456114 |
oct | 316620611657673 |
9 | 55273444673054 |
10 | 14210002542523 |
11 | 4589478a88057 |
12 | 1715bb1124bb7 |
13 | 7c0cc7640928 |
14 | 371aa6b7520b |
15 | 19997c583a9d |
hex | cec86275fbb |
14210002542523 has 12 divisors (see below), whose sum is σ = 14886499767048. Its totient is φ = 13563070806560.
The previous prime is 14210002542511. The next prime is 14210002542607. The reversal of 14210002542523 is 32524520001241.
It is a happy number.
It is not a de Polignac number, because 14210002542523 - 29 = 14210002542011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14210002542023) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 28513138 + ... + 29007223.
It is an arithmetic number, because the mean of its divisors is an integer number (1240541647254).
Almost surely, 214210002542523 is an apocalyptic number.
14210002542523 is a deficient number, since it is larger than the sum of its proper divisors (676497224525).
14210002542523 is an equidigital number, since it uses as much as digits as its factorization.
14210002542523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57520874 (or 57520851 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 14210002542523 its reverse (32524520001241), we get a palindrome (46734522543764).
The spelling of 14210002542523 in words is "fourteen trillion, two hundred ten billion, two million, five hundred forty-two thousand, five hundred twenty-three".
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