142100113 has 4 divisors (see below), whose sum is σ = 142294708. Its totient is φ = 141905520.

The previous prime is 142100051. The next prime is 142100149. The reversal of 142100113 is 311001241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 131262849 + 10837264 = 11457^2 + 3292^2 .

It is a cyclic number.

It is not a de Polignac number, because 142100113 - 2¹³ = 142091921 is a prime.

It is a super-2 number, since 2×142100113² = 40384884229225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142100093 and 142100102.

It is not an unprimeable number, because it can be changed into a prime (142100713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96198 + ... + 97663.

It is an arithmetic number, because the mean of its divisors is an integer number (35573677).

Almost surely, 2^142100113 is an apocalyptic number.

It is an amenable number.

142100113 is a deficient number, since it is larger than the sum of its proper divisors (194595).

142100113 is an equidigital number, since it uses as much as digits as its factorization.

142100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194594.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 142100113 is about 11920.5751958536. The cubic root of 142100113 is about 521.8329214307.

Adding to 142100113 its reverse (311001241), we get a palindrome (453101354).

The spelling of 142100113 in words is "one hundred forty-two million, one hundred thousand, one hundred thirteen".