142100440104111 has 4 divisors (see below), whose sum is σ = 189467253472152. Its totient is φ = 94733626736072.

The previous prime is 142100440104109. The next prime is 142100440104137. The reversal of 142100440104111 is 111401044001241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142100440104111 - 2¹ = 142100440104109 is a prime.

It is a super-3 number, since 3×142100440104111³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142100440104191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23683406684016 + ... + 23683406684021.

It is an arithmetic number, because the mean of its divisors is an integer number (47366813368038).

Almost surely, 2^{142100440104111} is an apocalyptic number.

142100440104111 is a deficient number, since it is larger than the sum of its proper divisors (47366813368041).

142100440104111 is an equidigital number, since it uses as much as digits as its factorization.

142100440104111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47366813368040.

The product of its (nonzero) digits is 512, while the sum is 24.

Adding to 142100440104111 its reverse (111401044001241), we get a palindrome (253501484105352).

The spelling of 142100440104111 in words is "one hundred forty-two trillion, one hundred billion, four hundred forty million, one hundred four thousand, one hundred eleven".