142102103415133 has 4 divisors (see below), whose sum is σ = 146686042235008. Its totient is φ = 137518164595260.

The previous prime is 142102103415059. The next prime is 142102103415137. The reversal of 142102103415133 is 331514301201241.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142102103415133 - 2³⁷ = 141964664461661 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 4583938819843 = 142102103415133 / (1 + 4 + 2 + 1 + 0 + 2 + 1 + 0 + 3 + 4 + 1 + 5 + 1 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142102103415095 and 142102103415104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142102103415137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2291969409891 + ... + 2291969409952.

It is an arithmetic number, because the mean of its divisors is an integer number (36671510558752).

Almost surely, 2^{142102103415133} is an apocalyptic number.

It is an amenable number.

142102103415133 is a deficient number, since it is larger than the sum of its proper divisors (4583938819875).

142102103415133 is an equidigital number, since it uses as much as digits as its factorization.

142102103415133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4583938819874.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 142102103415133 its reverse (331514301201241), we get a palindrome (473616404616374).

The spelling of 142102103415133 in words is "one hundred forty-two trillion, one hundred two billion, one hundred three million, four hundred fifteen thousand, one hundred thirty-three".