Base | Representation |
---|---|
bin | 1100111011001001111001… |
… | …1100010011010000011011 |
3 | 1212022111112220112011120021 |
4 | 3032302132130103100123 |
5 | 3330310404432043303 |
6 | 50120101112211311 |
7 | 2664445131212365 |
oct | 316623634232033 |
9 | 55274486464507 |
10 | 14210410034203 |
11 | 4589667aaa639 |
12 | 17160a5699b37 |
13 | 7c1060ba6176 |
14 | 371b04d29d35 |
15 | 1999a3226ebd |
hex | cec9e71341b |
14210410034203 has 2 divisors, whose sum is σ = 14210410034204. Its totient is φ = 14210410034202.
The previous prime is 14210410034201. The next prime is 14210410034269. The reversal of 14210410034203 is 30243001401241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14210410034203 - 21 = 14210410034201 is a prime.
Together with 14210410034201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (14210410034201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105205017101 + 7105205017102.
It is an arithmetic number, because the mean of its divisors is an integer number (7105205017102).
Almost surely, 214210410034203 is an apocalyptic number.
14210410034203 is a deficient number, since it is larger than the sum of its proper divisors (1).
14210410034203 is an equidigital number, since it uses as much as digits as its factorization.
14210410034203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14210410034203 its reverse (30243001401241), we get a palindrome (44453411435444).
The spelling of 14210410034203 in words is "fourteen trillion, two hundred ten billion, four hundred ten million, thirty-four thousand, two hundred three".
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