1421041130021 has 2 divisors, whose sum is σ = 1421041130022. Its totient is φ = 1421041130020.

The previous prime is 1421041130017. The next prime is 1421041130023. The reversal of 1421041130021 is 1200311401241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1163140680100 + 257900449921 = 1078490^2 + 507839^2 .

It is a cyclic number.

It is not a de Polignac number, because 1421041130021 - 2² = 1421041130017 is a prime.

It is a super-2 number, since 2×1421041130021² (a number of 25 digits) contains 22 as substring.

Together with 1421041130023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1421041129975 and 1421041130002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1421041130023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710520565010 + 710520565011.

It is an arithmetic number, because the mean of its divisors is an integer number (710520565011).

Almost surely, 2^{1421041130021} is an apocalyptic number.

It is an amenable number.

1421041130021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421041130021 is an equidigital number, since it uses as much as digits as its factorization.

1421041130021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1421041130021 its reverse (1200311401241), we get a palindrome (2621352531262).

The spelling of 1421041130021 in words is "one trillion, four hundred twenty-one billion, forty-one million, one hundred thirty thousand, twenty-one".