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142112124110111 = 308346095401917
BaseRepresentation
bin100000010100000000001110…
…101011010000010100011111
3200122011210020021101100020012
4200110000032223100110133
5122111331112233010421
61222125224124513435
741635155626016341
oct4024001653202437
9618153207340205
10142112124110111
1141310460228541
1213b323469ab87b
13613b16755194c
1427143990c5291
1511669e0cdc95b
hex81400ead051f

142112124110111 has 4 divisors (see below), whose sum is σ = 142158219515112. Its totient is φ = 142066028705112.

The previous prime is 142112124110087. The next prime is 142112124110153. The reversal of 142112124110111 is 111011421211241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142112124110111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142112124110911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23047697876 + ... + 23047704041.

It is an arithmetic number, because the mean of its divisors is an integer number (35539554878778).

Almost surely, 2142112124110111 is an apocalyptic number.

142112124110111 is a deficient number, since it is larger than the sum of its proper divisors (46095405001).

142112124110111 is an equidigital number, since it uses as much as digits as its factorization.

142112124110111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46095405000.

The product of its (nonzero) digits is 128, while the sum is 23.

Adding to 142112124110111 its reverse (111011421211241), we get a palindrome (253123545321352).

The spelling of 142112124110111 in words is "one hundred forty-two trillion, one hundred twelve billion, one hundred twenty-four million, one hundred ten thousand, one hundred eleven".

Divisors: 1 3083 46095401917 142112124110111