1421131054391 has 2 divisors, whose sum is σ = 1421131054392. Its totient is φ = 1421131054390.

The previous prime is 1421131054363. The next prime is 1421131054403. The reversal of 1421131054391 is 1934501311241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1421131054391 - 2¹⁰ = 1421131053367 is a prime.

It is a super-2 number, since 2×1421131054391² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1421131054351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710565527195 + 710565527196.

It is an arithmetic number, because the mean of its divisors is an integer number (710565527196).

Almost surely, 2^{1421131054391} is an apocalyptic number.

1421131054391 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421131054391 is an equidigital number, since it uses as much as digits as its factorization.

1421131054391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 35.

The spelling of 1421131054391 in words is "one trillion, four hundred twenty-one billion, one hundred thirty-one million, fifty-four thousand, three hundred ninety-one".