Base | Representation |
---|---|
bin | 10100101011100010000… |
… | …000101111110100001111 |
3 | 12000212012001210120121111 |
4 | 110223202000233310033 |
5 | 141240434022214401 |
6 | 3004505242312451 |
7 | 204446644436341 |
oct | 24534200576417 |
9 | 5025161716544 |
10 | 1421131054351 |
11 | 4a8775482178 |
12 | 1ab511ab8727 |
13 | a4020716328 |
14 | 4cad6bd5291 |
15 | 26e78347e51 |
hex | 14ae202fd0f |
1421131054351 has 2 divisors, whose sum is σ = 1421131054352. Its totient is φ = 1421131054350.
The previous prime is 1421131054333. The next prime is 1421131054363. The reversal of 1421131054351 is 1534501311241.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1534501311241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1421131054351 - 25 = 1421131054319 is a prime.
It is a super-2 number, since 2×14211310543512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1421131054391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710565527175 + 710565527176.
It is an arithmetic number, because the mean of its divisors is an integer number (710565527176).
Almost surely, 21421131054351 is an apocalyptic number.
1421131054351 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421131054351 is an equidigital number, since it uses as much as digits as its factorization.
1421131054351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 1421131054351 its reverse (1534501311241), we get a palindrome (2955632365592).
The spelling of 1421131054351 in words is "one trillion, four hundred twenty-one billion, one hundred thirty-one million, fifty-four thousand, three hundred fifty-one".
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