Search a number
-
+
14211343757 = 135419201731
BaseRepresentation
bin11010011110000111…
…11110010110001101
31100200102011001201002
431033003332112031
5213101101000012
610310102230045
71012112300042
oct151703762615
940612131632
1014211343757
116032a299a6
122907425325
131456338560
1498b5ad1c9
1558297d7c2
hex34f0fe58d

14211343757 has 8 divisors (see below), whose sum is σ = 15307424160. Its totient is φ = 13115677680.

The previous prime is 14211343739. The next prime is 14211343771. The reversal of 14211343757 is 75734311241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14211343757 - 28 = 14211343501 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14211343757.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14211342757) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30419 + ... + 171312.

It is an arithmetic number, because the mean of its divisors is an integer number (1913428020).

Almost surely, 214211343757 is an apocalyptic number.

It is an amenable number.

14211343757 is a deficient number, since it is larger than the sum of its proper divisors (1096080403).

14211343757 is a wasteful number, since it uses less digits than its factorization.

14211343757 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 207163.

The product of its digits is 70560, while the sum is 38.

Adding to 14211343757 its reverse (75734311241), we get a palindrome (89945654998).

The spelling of 14211343757 in words is "fourteen billion, two hundred eleven million, three hundred forty-three thousand, seven hundred fifty-seven".

Divisors: 1 13 5419 70447 201731 2622503 1093180289 14211343757