Base | Representation |
---|---|
bin | 1100111011001110001000… |
… | …0011010111110101100110 |
3 | 1212022121110221221101101110 |
4 | 3032303202003113311212 |
5 | 3330320220323200204 |
6 | 50120405432405450 |
7 | 2664515213560602 |
oct | 316634203276546 |
9 | 55277427841343 |
10 | 14211544350054 |
11 | 458a09a322957 |
12 | 1716361546886 |
13 | 7c11b1bb038c |
14 | 371bb183c502 |
15 | 199a1cada889 |
hex | cece20d7d66 |
14211544350054 has 32 divisors (see below), whose sum is σ = 30101548759776. Its totient is φ = 4457558730240.
The previous prime is 14211544350049. The next prime is 14211544350097. The reversal of 14211544350054 is 45005344511241.
It is a junction number, because it is equal to n+sod(n) for n = 14211544349994 and 14211544350021.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14604277 + ... + 15546960.
It is an arithmetic number, because the mean of its divisors is an integer number (940673398743).
Almost surely, 214211544350054 is an apocalyptic number.
14211544350054 is an abundant number, since it is smaller than the sum of its proper divisors (15890004409722).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14211544350054 is a wasteful number, since it uses less digits than its factorization.
14211544350054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30155880.
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 14211544350054 its reverse (45005344511241), we get a palindrome (59216888861295).
The spelling of 14211544350054 in words is "fourteen trillion, two hundred eleven billion, five hundred forty-four million, three hundred fifty thousand, fifty-four".
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