Base | Representation |
---|---|
bin | 1000010001011100010… |
… | …1011110001101100111 |
3 | 111120211200011120220222 |
4 | 2010113011132031213 |
5 | 4312031013344312 |
6 | 145142315114555 |
7 | 13160616350564 |
oct | 2042705361547 |
9 | 446750146828 |
10 | 142121231207 |
11 | 5530080358a |
12 | 23664142a5b |
13 | 1052c1a47a7 |
14 | 6c4324386b |
15 | 3a6c07e672 |
hex | 211715e367 |
142121231207 has 2 divisors, whose sum is σ = 142121231208. Its totient is φ = 142121231206.
The previous prime is 142121231183. The next prime is 142121231221. The reversal of 142121231207 is 702132121241.
It is a happy number.
142121231207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142121231207 - 222 = 142117036903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142121231227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71060615603 + 71060615604.
It is an arithmetic number, because the mean of its divisors is an integer number (71060615604).
Almost surely, 2142121231207 is an apocalyptic number.
142121231207 is a deficient number, since it is larger than the sum of its proper divisors (1).
142121231207 is an equidigital number, since it uses as much as digits as its factorization.
142121231207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 142121231207 its reverse (702132121241), we get a palindrome (844253352448).
The spelling of 142121231207 in words is "one hundred forty-two billion, one hundred twenty-one million, two hundred thirty-one thousand, two hundred seven".
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