Search a number
-
+
1421221033 = 1974801107
BaseRepresentation
bin101010010110110…
…0001110010101001
310200001021111202001
41110231201302221
510402313033113
6353005411001
750135115361
oct12455416251
93601244661
101421221033
1166a273441
12337b69a61
1319859b8bb
14d6a779a1
1584b877dd
hex54b61ca9

1421221033 has 4 divisors (see below), whose sum is σ = 1496022160. Its totient is φ = 1346419908.

The previous prime is 1421220959. The next prime is 1421221057. The reversal of 1421221033 is 3301221241.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1421221033 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 74801107 = 1421221033 / (1 + 4 + 2 + 1 + 2 + 2 + 1 + 0 + 3 + 3).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1421221033.

It is not an unprimeable number, because it can be changed into a prime (1421221073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37400535 + ... + 37400572.

It is an arithmetic number, because the mean of its divisors is an integer number (374005540).

Almost surely, 21421221033 is an apocalyptic number.

It is an amenable number.

1421221033 is a deficient number, since it is larger than the sum of its proper divisors (74801127).

1421221033 is an equidigital number, since it uses as much as digits as its factorization.

1421221033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74801126.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 1421221033 is about 37699.0853072061. The cubic root of 1421221033 is about 1124.3129389685.

Adding to 1421221033 its reverse (3301221241), we get a palindrome (4722442274).

It can be divided in two parts, 14212 and 21033, that added together give a triangular number (35245 = T265).

The spelling of 1421221033 in words is "one billion, four hundred twenty-one million, two hundred twenty-one thousand, thirty-three".

Divisors: 1 19 74801107 1421221033