14212442133301 has 4 divisors (see below), whose sum is σ = 14212485809100. Its totient is φ = 14212398457504.

The previous prime is 14212442133299. The next prime is 14212442133313. The reversal of 14212442133301 is 10333124421241.

It is a happy number.

14212442133301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7792304760900 + 6420137372401 = 2791470^2 + 2533799^2 .

It is a cyclic number.

It is not a de Polignac number, because 14212442133301 - 2¹ = 14212442133299 is a prime.

It is a super-2 number, since 2×14212442133301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14212442133391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21346096 + ... + 22001833.

It is an arithmetic number, because the mean of its divisors is an integer number (3553121452275).

Almost surely, 2^{14212442133301} is an apocalyptic number.

It is an amenable number.

14212442133301 is a deficient number, since it is larger than the sum of its proper divisors (43675799).

14212442133301 is an equidigital number, since it uses as much as digits as its factorization.

14212442133301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43675798.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 14212442133301 its reverse (10333124421241), we get a palindrome (24545566554542).

The spelling of 14212442133301 in words is "fourteen trillion, two hundred twelve billion, four hundred forty-two million, one hundred thirty-three thousand, three hundred one".