Base | Representation |
---|---|
bin | 1100111011010011111110… |
… | …0000001111101110101000 |
3 | 1212022202112020010102022211 |
4 | 3032310333200033232220 |
5 | 3330331423210400404 |
6 | 50121225201054504 |
7 | 2664602112226156 |
oct | 316647740175650 |
9 | 55282466112284 |
10 | 14213112200104 |
11 | 458a8243358a4 |
12 | 171671a627434 |
13 | 7c13a196a6bc |
14 | 371cbdb643d6 |
15 | 199ab0588b04 |
hex | ced3f80fba8 |
14213112200104 has 8 divisors (see below), whose sum is σ = 26649585375210. Its totient is φ = 7106556100048.
The previous prime is 14213112200083. The next prime is 14213112200117. The reversal of 14213112200104 is 40100221131241.
It can be written as a sum of positive squares in only one way, i.e., 8865446700100 + 5347665500004 = 2977490^2 + 2312502^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is a super-2 number, since 2×142131122001042 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 888319512499 + ... + 888319512514.
Almost surely, 214213112200104 is an apocalyptic number.
It is an amenable number.
14213112200104 is a deficient number, since it is larger than the sum of its proper divisors (12436473175106).
14213112200104 is a wasteful number, since it uses less digits than its factorization.
14213112200104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1776639025019 (or 1776639025015 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 14213112200104 its reverse (40100221131241), we get a palindrome (54313333331345).
The spelling of 14213112200104 in words is "fourteen trillion, two hundred thirteen billion, one hundred twelve million, two hundred thousand, one hundred four".
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