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14213121024343 = 54725983767869
BaseRepresentation
bin1100111011010100000000…
…0001111010000101010111
31212022202112211201201220111
43032311000001322011113
53330331432440234333
650121230114143451
72664602250230623
oct316650001720527
955282484651814
1014213121024343
11458a82931265a
121716721581b87
137c13a373a047
14371cc0dc0183
15199ab122d4cd
hexced4007a157

14213121024343 has 4 divisors (see below), whose sum is σ = 14239104792760. Its totient is φ = 14187137255928.

The previous prime is 14213121024307. The next prime is 14213121024383. The reversal of 14213121024343 is 34342012131241.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14213121024343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14213121024383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12991883388 + ... + 12991884481.

It is an arithmetic number, because the mean of its divisors is an integer number (3559776198190).

Almost surely, 214213121024343 is an apocalyptic number.

14213121024343 is a deficient number, since it is larger than the sum of its proper divisors (25983768417).

14213121024343 is an equidigital number, since it uses as much as digits as its factorization.

14213121024343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25983768416.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 14213121024343 its reverse (34342012131241), we get a palindrome (48555133155584).

The spelling of 14213121024343 in words is "fourteen trillion, two hundred thirteen billion, one hundred twenty-one million, twenty-four thousand, three hundred forty-three".

Divisors: 1 547 25983767869 14213121024343