Base | Representation |
---|---|
bin | 1100111011010100000000… |
… | …1010110000011001000111 |
3 | 1212022202120000002120210121 |
4 | 3032311000022300121013 |
5 | 3330331434034001233 |
6 | 50121230240002411 |
7 | 2664602306031406 |
oct | 316650012603107 |
9 | 55282500076717 |
10 | 14213123343943 |
11 | 458a82a657387 |
12 | 1716722300407 |
13 | 7c13a406caa4 |
14 | 371cc142563d |
15 | 199ab153a92d |
hex | ced402b0647 |
14213123343943 has 2 divisors, whose sum is σ = 14213123343944. Its totient is φ = 14213123343942.
The previous prime is 14213123343919. The next prime is 14213123344027. The reversal of 14213123343943 is 34934332131241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14213123343943 - 213 = 14213123335751 is a prime.
It is a super-3 number, since 3×142131233439433 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14213123343943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14213123343743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106561671971 + 7106561671972.
It is an arithmetic number, because the mean of its divisors is an integer number (7106561671972).
Almost surely, 214213123343943 is an apocalyptic number.
14213123343943 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213123343943 is an equidigital number, since it uses as much as digits as its factorization.
14213123343943 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 559872, while the sum is 43.
The spelling of 14213123343943 in words is "fourteen trillion, two hundred thirteen billion, one hundred twenty-three million, three hundred forty-three thousand, nine hundred forty-three".
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