Base | Representation |
---|---|
bin | 1100111011010100000000… |
… | …1010110000011010011011 |
3 | 1212022202120000002120220201 |
4 | 3032311000022300122123 |
5 | 3330331434034002102 |
6 | 50121230240003031 |
7 | 2664602306031556 |
oct | 316650012603233 |
9 | 55282500076821 |
10 | 14213123344027 |
11 | 458a82a657453 |
12 | 1716722300477 |
13 | 7c13a406cb3a |
14 | 371cc142569d |
15 | 199ab153a987 |
hex | ced402b069b |
14213123344027 has 2 divisors, whose sum is σ = 14213123344028. Its totient is φ = 14213123344026.
The previous prime is 14213123343943. The next prime is 14213123344097. The reversal of 14213123344027 is 72044332131241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14213123344027 - 215 = 14213123311259 is a prime.
It is not a weakly prime, because it can be changed into another prime (14213123344097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106561672013 + 7106561672014.
It is an arithmetic number, because the mean of its divisors is an integer number (7106561672014).
Almost surely, 214213123344027 is an apocalyptic number.
14213123344027 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213123344027 is an equidigital number, since it uses as much as digits as its factorization.
14213123344027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 37.
Adding to 14213123344027 its reverse (72044332131241), we get a palindrome (86257455475268).
The spelling of 14213123344027 in words is "fourteen trillion, two hundred thirteen billion, one hundred twenty-three million, three hundred forty-four thousand, twenty-seven".
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