Base | Representation |
---|---|
bin | 1100111011010100000100… |
… | …1010011011001000111110 |
3 | 1212022202121011111112101221 |
4 | 3032311001022123020332 |
5 | 3330332002322042420 |
6 | 50121232033423554 |
7 | 2664602600633653 |
oct | 316650112331076 |
9 | 55282534445357 |
10 | 14213140034110 |
11 | 458a839016a06 |
12 | 1716727a0abba |
13 | 7c13a7664824 |
14 | 371cc372bc2a |
15 | 199ab2c35caa |
hex | ced4129b23e |
14213140034110 has 16 divisors (see below), whose sum is σ = 27088572771216. Its totient is φ = 5350829189248.
The previous prime is 14213140034083. The next prime is 14213140034123. The reversal of 14213140034110 is 1143004131241.
14213140034110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41803352872 + ... + 41803353211.
It is an arithmetic number, because the mean of its divisors is an integer number (1693035798201).
Almost surely, 214213140034110 is an apocalyptic number.
14213140034110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14213140034110 is a deficient number, since it is larger than the sum of its proper divisors (12875432737106).
14213140034110 is a wasteful number, since it uses less digits than its factorization.
14213140034110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83606706107.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14213140034110 its reverse (1143004131241), we get a palindrome (15356144165351).
The spelling of 14213140034110 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty million, thirty-four thousand, one hundred ten".
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