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14213140034110 = 251783606706083
BaseRepresentation
bin1100111011010100000100…
…1010011011001000111110
31212022202121011111112101221
43032311001022123020332
53330332002322042420
650121232033423554
72664602600633653
oct316650112331076
955282534445357
1014213140034110
11458a839016a06
121716727a0abba
137c13a7664824
14371cc372bc2a
15199ab2c35caa
hexced4129b23e

14213140034110 has 16 divisors (see below), whose sum is σ = 27088572771216. Its totient is φ = 5350829189248.

The previous prime is 14213140034083. The next prime is 14213140034123. The reversal of 14213140034110 is 1143004131241.

14213140034110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41803352872 + ... + 41803353211.

It is an arithmetic number, because the mean of its divisors is an integer number (1693035798201).

Almost surely, 214213140034110 is an apocalyptic number.

14213140034110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14213140034110 is a deficient number, since it is larger than the sum of its proper divisors (12875432737106).

14213140034110 is a wasteful number, since it uses less digits than its factorization.

14213140034110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83606706107.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14213140034110 its reverse (1143004131241), we get a palindrome (15356144165351).

The spelling of 14213140034110 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty million, thirty-four thousand, one hundred ten".

Divisors: 1 2 5 10 17 34 85 170 83606706083 167213412166 418033530415 836067060830 1421314003411 2842628006822 7106570017055 14213140034110