Base | Representation |
---|---|
bin | 1100111011010100000100… |
… | …1010101110011010100011 |
3 | 1212022202121011122112200222 |
4 | 3032311001022232122203 |
5 | 3330332002332104214 |
6 | 50121232035233255 |
7 | 2664602601413066 |
oct | 316650112563243 |
9 | 55282534575628 |
10 | 14213140113059 |
11 | 458a839070258 |
12 | 1716727a4882b |
13 | 7c13a7691744 |
14 | 371cc374c8dd |
15 | 199ab2c4e38e |
hex | ced412ae6a3 |
14213140113059 has 2 divisors, whose sum is σ = 14213140113060. Its totient is φ = 14213140113058.
The previous prime is 14213140113047. The next prime is 14213140113071. The reversal of 14213140113059 is 95031104131241.
14213140113059 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (14213140113047) and next prime (14213140113071).
It is a cyclic number.
It is not a de Polignac number, because 14213140113059 - 212 = 14213140108963 is a prime.
It is not a weakly prime, because it can be changed into another prime (14213140113089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106570056529 + 7106570056530.
It is an arithmetic number, because the mean of its divisors is an integer number (7106570056530).
Almost surely, 214213140113059 is an apocalyptic number.
14213140113059 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213140113059 is an equidigital number, since it uses as much as digits as its factorization.
14213140113059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 14213140113059 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty million, one hundred thirteen thousand, fifty-nine".
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