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14213140113047 is a prime number
BaseRepresentation
bin1100111011010100000100…
…1010101110011010010111
31212022202121011122112200112
43032311001022232122113
53330332002332104142
650121232035233235
72664602601413051
oct316650112563227
955282534575615
1014213140113047
11458a839070247
121716727a4881b
137c13a7691735
14371cc374c8d1
15199ab2c4e382
hexced412ae697

14213140113047 has 2 divisors, whose sum is σ = 14213140113048. Its totient is φ = 14213140113046.

The previous prime is 14213140112987. The next prime is 14213140113059. The reversal of 14213140113047 is 74031104131241.

It is a strong prime.

It is an emirp because it is prime and its reverse (74031104131241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14213140113047 - 210 = 14213140112023 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14213140113077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106570056523 + 7106570056524.

It is an arithmetic number, because the mean of its divisors is an integer number (7106570056524).

Almost surely, 214213140113047 is an apocalyptic number.

14213140113047 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213140113047 is an equidigital number, since it uses as much as digits as its factorization.

14213140113047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 32.

Adding to 14213140113047 its reverse (74031104131241), we get a palindrome (88244244244288).

The spelling of 14213140113047 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty million, one hundred thirteen thousand, forty-seven".