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14213301 = 34737767
BaseRepresentation
bin110110001110…
…000010110101
3222202002222120
4312032002311
512114311201
61224350153
7231545124
oct66160265
928662876
1014213301
118028733
124915359
132c3854b
141c5dabb
1513ab536
hexd8e0b5

14213301 has 4 divisors (see below), whose sum is σ = 18951072. Its totient is φ = 9475532.

The previous prime is 14213299. The next prime is 14213327. The reversal of 14213301 is 10331241.

14213301 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14213301 - 21 = 14213299 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14213371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368881 + ... + 2368886.

It is an arithmetic number, because the mean of its divisors is an integer number (4737768).

Almost surely, 214213301 is an apocalyptic number.

It is an amenable number.

14213301 is a deficient number, since it is larger than the sum of its proper divisors (4737771).

14213301 is an equidigital number, since it uses as much as digits as its factorization.

14213301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4737770.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 14213301 is about 3770.0531826488. The cubic root of 14213301 is about 242.2320759380.

Adding to 14213301 its reverse (10331241), we get a palindrome (24544542).

The spelling of 14213301 in words is "fourteen million, two hundred thirteen thousand, three hundred one".

Divisors: 1 3 4737767 14213301