Base | Representation |
---|---|
bin | 11010011110010111… |
… | …11100000000100011 |
3 | 1100200120002010022122 |
4 | 31033023330000203 |
5 | 213102114300311 |
6 | 10310215054455 |
7 | 1012136113211 |
oct | 151713740043 |
9 | 40616063278 |
10 | 14213431331 |
11 | 6034125370 |
12 | 290807142b |
13 | 14568b97c8 |
14 | 98b993cb1 |
15 | 582c420db |
hex | 34f2fc023 |
14213431331 has 8 divisors (see below), whose sum is σ = 15759751728. Its totient is φ = 12709476000.
The previous prime is 14213431321. The next prime is 14213431333. The reversal of 14213431331 is 13313431241.
14213431331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14213431331 is a prime.
It is a super-2 number, since 2×142134313312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14213431331.
It is not an unprimeable number, because it can be changed into a prime (14213431333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10590560 + ... + 10591901.
It is an arithmetic number, because the mean of its divisors is an integer number (1969968966).
Almost surely, 214213431331 is an apocalyptic number.
14213431331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14213431331 is a deficient number, since it is larger than the sum of its proper divisors (1546320397).
14213431331 is a wasteful number, since it uses less digits than its factorization.
14213431331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21182533.
The product of its digits is 2592, while the sum is 26.
Adding to 14213431331 its reverse (13313431241), we get a palindrome (27526862572).
It can be divided in two parts, 14213 and 431331, that added together give a palindrome (445544).
The spelling of 14213431331 in words is "fourteen billion, two hundred thirteen million, four hundred thirty-one thousand, three hundred thirty-one".
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