Base | Representation |
---|---|
bin | 11010011110010111… |
… | …11110011100110101 |
3 | 1100200120002122001002 |
4 | 31033023332130311 |
5 | 213102120110313 |
6 | 10310215213045 |
7 | 1012136154320 |
oct | 151713763465 |
9 | 40616078032 |
10 | 14213441333 |
11 | 6034131933 |
12 | 2908077185 |
13 | 14568c1220 |
14 | 98b9977b7 |
15 | 582c45058 |
hex | 34f2fe735 |
14213441333 has 32 divisors (see below), whose sum is σ = 17642311680. Its totient is φ = 11150550720.
The previous prime is 14213441329. The next prime is 14213441351. The reversal of 14213441333 is 33314431241.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 14213441333 - 22 = 14213441329 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14213441296 and 14213441305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14213441233) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5596778 + ... + 5599316.
It is an arithmetic number, because the mean of its divisors is an integer number (551322240).
Almost surely, 214213441333 is an apocalyptic number.
14213441333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
14213441333 is a deficient number, since it is larger than the sum of its proper divisors (3428870347).
14213441333 is a wasteful number, since it uses less digits than its factorization.
14213441333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3057.
The product of its digits is 10368, while the sum is 29.
Adding to 14213441333 its reverse (33314431241), we get a palindrome (47527872574).
The spelling of 14213441333 in words is "fourteen billion, two hundred thirteen million, four hundred forty-one thousand, three hundred thirty-three".
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