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14213552453 is a prime number
BaseRepresentation
bin11010011110011000…
…11001100101000101
31100200120022021110122
431033030121211011
5213102132134303
610310221431325
71012140126302
oct151714314505
940616267418
1014213552453
1160341a8371
12290810b545
13145692c989
1498b9c60a9
15582c67e38
hex34f319945

14213552453 has 2 divisors, whose sum is σ = 14213552454. Its totient is φ = 14213552452.

The previous prime is 14213552411. The next prime is 14213552467. The reversal of 14213552453 is 35425531241.

14213552453 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14104412644 + 109139809 = 118762^2 + 10447^2 .

It is an emirp because it is prime and its reverse (35425531241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14213552453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14213552653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106776226 + 7106776227.

It is an arithmetic number, because the mean of its divisors is an integer number (7106776227).

Almost surely, 214213552453 is an apocalyptic number.

It is an amenable number.

14213552453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213552453 is an equidigital number, since it uses as much as digits as its factorization.

14213552453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72000, while the sum is 35.

The spelling of 14213552453 in words is "fourteen billion, two hundred thirteen million, five hundred fifty-two thousand, four hundred fifty-three".