142140533 has 2 divisors, whose sum is σ = 142140534. Its totient is φ = 142140532.

The previous prime is 142140527. The next prime is 142140613. The reversal of 142140533 is 335041241.

142140533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139759684 + 2380849 = 11822^2 + 1543^2 .

It is an emirp because it is prime and its reverse (335041241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142140533 - 2⁴ = 142140517 is a prime.

It is a super-2 number, since 2×142140533² = 40407862243048178, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142140499 and 142140508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142140503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71070266 + 71070267.

It is an arithmetic number, because the mean of its divisors is an integer number (71070267).

Almost surely, 2^142140533 is an apocalyptic number.

It is an amenable number.

142140533 is a deficient number, since it is larger than the sum of its proper divisors (1).

142140533 is an equidigital number, since it uses as much as digits as its factorization.

142140533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 142140533 is about 11922.2704632968. The cubic root of 142140533 is about 521.8823947367.

Adding to 142140533 its reverse (335041241), we get a palindrome (477181774).

The spelling of 142140533 in words is "one hundred forty-two million, one hundred forty thousand, five hundred thirty-three".