Base | Representation |
---|---|
bin | 11010011110100110… |
… | …00111011011111001 |
3 | 1100200200121201200110 |
4 | 31033103013123321 |
5 | 213103110010040 |
6 | 10310323254533 |
7 | 1012161111435 |
oct | 151723073371 |
9 | 40620551613 |
10 | 14215313145 |
11 | 60351a0190 |
12 | 290881a449 |
13 | 14570c81c7 |
14 | 98bd239c5 |
15 | 582eb4980 |
hex | 34f4c76f9 |
14215313145 has 32 divisors (see below), whose sum is σ = 24845178240. Its totient is φ = 6883107840.
The previous prime is 14215313131. The next prime is 14215313173. The reversal of 14215313145 is 54131351241.
It is not a de Polignac number, because 14215313145 - 24 = 14215313129 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68001 + ... + 181809.
It is an arithmetic number, because the mean of its divisors is an integer number (776411820).
Almost surely, 214215313145 is an apocalyptic number.
14215313145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14215313145 is a deficient number, since it is larger than the sum of its proper divisors (10629865095).
14215313145 is a wasteful number, since it uses less digits than its factorization.
14215313145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114585.
The product of its digits is 7200, while the sum is 30.
Adding to 14215313145 its reverse (54131351241), we get a palindrome (68346664386).
The spelling of 14215313145 in words is "fourteen billion, two hundred fifteen million, three hundred thirteen thousand, one hundred forty-five".
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