Base | Representation |
---|---|
bin | 10100101011111010100… |
… | …101100010011011110101 |
3 | 12000220020210121110201202 |
4 | 110223322211202123311 |
5 | 141242310044231203 |
6 | 3005014211302245 |
7 | 204463112060426 |
oct | 24537245423365 |
9 | 5026223543652 |
10 | 1421543352053 |
11 | 4a8967187580 |
12 | 1ab607baa985 |
13 | a4087c72276 |
14 | 4cb3587b64d |
15 | 26e9e63a388 |
hex | 14afa9626f5 |
1421543352053 has 32 divisors (see below), whose sum is σ = 1608659880960. Its totient is φ = 1244491776000.
The previous prime is 1421543352049. The next prime is 1421543352067. The reversal of 1421543352053 is 3502533451241.
It is not a de Polignac number, because 1421543352053 - 22 = 1421543352049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1421543351998 and 1421543352016.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1421543352953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 122361701 + ... + 122373317.
It is an arithmetic number, because the mean of its divisors is an integer number (50270621280).
Almost surely, 21421543352053 is an apocalyptic number.
It is an amenable number.
1421543352053 is a deficient number, since it is larger than the sum of its proper divisors (187116528907).
1421543352053 is a wasteful number, since it uses less digits than its factorization.
1421543352053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13389.
The product of its (nonzero) digits is 216000, while the sum is 38.
The spelling of 1421543352053 in words is "one trillion, four hundred twenty-one billion, five hundred forty-three million, three hundred fifty-two thousand, fifty-three".
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