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142200413400 = 233521722216277
BaseRepresentation
bin1000010001101111001…
…1100001110011011000
3111121001012011110110210
42010123303201303120
54312211301212100
6145154224211120
713162600366503
oct2043363416330
9447035143423
10142200413400
1155341476311
1223686769aa0
1310542709866
146c4d97613a
153a73ec0c50
hex211bce1cd8

142200413400 has 192 divisors, whose sum is σ = 467036491680. Its totient is φ = 35667763200.

The previous prime is 142200413359. The next prime is 142200413449. The reversal of 142200413400 is 4314002241.

It is a super-2 number, since 2×1422004134002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 22651062 + ... + 22657338.

Almost surely, 2142200413400 is an apocalyptic number.

142200413400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 142200413400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233518245840).

142200413400 is an abundant number, since it is smaller than the sum of its proper divisors (324836078280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

142200413400 is a wasteful number, since it uses less digits than its factorization.

142200413400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8534 (or 8525 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 142200413400 its reverse (4314002241), we get a palindrome (146514415641).

The spelling of 142200413400 in words is "one hundred forty-two billion, two hundred million, four hundred thirteen thousand, four hundred".