Base | Representation |
---|---|
bin | 10100101100010111000… |
… | …111111010001001101111 |
3 | 12000221111011111121120101 |
4 | 110230113013322021233 |
5 | 141244300130433033 |
6 | 3005133513131531 |
7 | 204511014422425 |
oct | 24542707721157 |
9 | 5027434447511 |
10 | 1422022124143 |
11 | 4a9092465095 |
12 | 1ab7203b9ba7 |
13 | a413320406a |
14 | 4cb7d2a9115 |
15 | 26ecb6ad97d |
hex | 14b171fa26f |
1422022124143 has 4 divisors (see below), whose sum is σ = 1422040662040. Its totient is φ = 1422003586248.
The previous prime is 1422022124141. The next prime is 1422022124147. The reversal of 1422022124143 is 3414212202241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1422022124143 - 21 = 1422022124141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1422022124141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9153405 + ... + 9307462.
It is an arithmetic number, because the mean of its divisors is an integer number (355510165510).
Almost surely, 21422022124143 is an apocalyptic number.
1422022124143 is a deficient number, since it is larger than the sum of its proper divisors (18537897).
1422022124143 is an equidigital number, since it uses as much as digits as its factorization.
1422022124143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18537896.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 1422022124143 its reverse (3414212202241), we get a palindrome (4836234326384).
The spelling of 1422022124143 in words is "one trillion, four hundred twenty-two billion, twenty-two million, one hundred twenty-four thousand, one hundred forty-three".
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