14221115 has 4 divisors (see below), whose sum is σ = 17065344. Its totient is φ = 11376888.

The previous prime is 14221093. The next prime is 14221127. The reversal of 14221115 is 51112241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51112241 = 197 ⋅259453.

It is a cyclic number.

It is not a de Polignac number, because 14221115 - 2¹⁶ = 14155579 is a prime.

It is a super-2 number, since 2×14221115² = 404480223686450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14221093 and 14221102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1422107 + ... + 1422116.

It is an arithmetic number, because the mean of its divisors is an integer number (4266336).

Almost surely, 2^14221115 is an apocalyptic number.

14221115 is a deficient number, since it is larger than the sum of its proper divisors (2844229).

14221115 is an equidigital number, since it uses as much as digits as its factorization.

14221115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2844228.

The product of its digits is 80, while the sum is 17.

The square root of 14221115 is about 3771.0893651570. The cubic root of 14221115 is about 242.2764581843.

Adding to 14221115 its reverse (51112241), we get a palindrome (65333356).

The spelling of 14221115 in words is "fourteen million, two hundred twenty-one thousand, one hundred fifteen".