14221333312241 has 4 divisors (see below), whose sum is σ = 15514181795184. Its totient is φ = 12928484829300.

The previous prime is 14221333312211. The next prime is 14221333312253.

14221333312241 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14221333312241 - 2⁶ = 14221333312177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14221333312198 and 14221333312207.

It is not an unprimeable number, because it can be changed into a prime (14221333312211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 646424241455 + ... + 646424241476.

It is an arithmetic number, because the mean of its divisors is an integer number (3878545448796).

Almost surely, 2^{14221333312241} is an apocalyptic number.

14221333312241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14221333312241 is a deficient number, since it is larger than the sum of its proper divisors (1292848482943).

14221333312241 is a wasteful number, since it uses less digits than its factorization.

14221333312241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1292848482942.

The product of its digits is 20736, while the sum is 32.

It can be divided in two parts, 1422133 and 3312241, that added together give a palindrome (4734374).

The spelling of 14221333312241 in words is "fourteen trillion, two hundred twenty-one billion, three hundred thirty-three million, three hundred twelve thousand, two hundred forty-one".