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1422144422135 = 5491579284897
BaseRepresentation
bin10100101100011110011…
…010011100000011110111
312000221210200121222212122
4110230132122130003313
5141300022433002020
63005154002310155
7204514031064353
oct24543632340367
95027720558778
101422144422135
114a91454a6408
121ab75535835b
13a4152653c38
144cb91622463
1526ed72ba125
hex14b1e69c0f7

1422144422135 has 8 divisors (see below), whose sum is σ = 1710049018896. Its totient is φ = 1135398396160.

The previous prime is 1422144422129. The next prime is 1422144422147. The reversal of 1422144422135 is 5312244412241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1422144422135 - 24 = 1422144422119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1422144422095 and 1422144422104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 289639994 + ... + 289644903.

It is an arithmetic number, because the mean of its divisors is an integer number (213756127362).

Almost surely, 21422144422135 is an apocalyptic number.

1422144422135 is a deficient number, since it is larger than the sum of its proper divisors (287904596761).

1422144422135 is an equidigital number, since it uses as much as digits as its factorization.

1422144422135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 579285393.

The product of its digits is 61440, while the sum is 35.

Adding to 1422144422135 its reverse (5312244412241), we get a palindrome (6734388834376).

The spelling of 1422144422135 in words is "one trillion, four hundred twenty-two billion, one hundred forty-four million, four hundred twenty-two thousand, one hundred thirty-five".

Divisors: 1 5 491 2455 579284897 2896424485 284428884427 1422144422135