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142221131413 is a prime number
BaseRepresentation
bin1000010001110100001…
…0100011111010010101
3111121002122011001020121
42010131002203322111
54312232102201123
6145200244231541
713163241446044
oct2043502437225
9447078131217
10142221131413
1155352137039
122369169b5b1
1310546ab1a3a
146c5260a55b
153a75c1475d
hex211d0a3e95

142221131413 has 2 divisors, whose sum is σ = 142221131414. Its totient is φ = 142221131412.

The previous prime is 142221131401. The next prime is 142221131447. The reversal of 142221131413 is 314131122241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 141374496004 + 846635409 = 375998^2 + 29097^2 .

It is a cyclic number.

It is not a de Polignac number, because 142221131413 - 221 = 142219034261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142221138413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71110565706 + 71110565707.

It is an arithmetic number, because the mean of its divisors is an integer number (71110565707).

Almost surely, 2142221131413 is an apocalyptic number.

It is an amenable number.

142221131413 is a deficient number, since it is larger than the sum of its proper divisors (1).

142221131413 is an equidigital number, since it uses as much as digits as its factorization.

142221131413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 142221131413 its reverse (314131122241), we get a palindrome (456352253654).

The spelling of 142221131413 in words is "one hundred forty-two billion, two hundred twenty-one million, one hundred thirty-one thousand, four hundred thirteen".