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142232234441 = 11107811199351
BaseRepresentation
bin1000010001110110110…
…0111010100111001001
3111121010102001010201212
42010131230322213021
54312242423000231
6145201322222505
713163435021303
oct2043554724711
9447112033655
10142232234441
115535842a9a0
1223695354a35
131054919b68b
146c53c9a973
153a76ba942b
hex211db3a9c9

142232234441 has 8 divisors (see below), whose sum is σ = 155176959168. Its totient is φ = 129289930000.

The previous prime is 142232234423. The next prime is 142232234471. The reversal of 142232234441 is 144432232241.

It is a happy number.

142232234441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 142232234441 - 214 = 142232218057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142232234398 and 142232234407.

It is not an unprimeable number, because it can be changed into a prime (142232234411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481085 + ... + 718266.

It is an arithmetic number, because the mean of its divisors is an integer number (19397119896).

Almost surely, 2142232234441 is an apocalyptic number.

142232234441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

142232234441 is a deficient number, since it is larger than the sum of its proper divisors (12944724727).

142232234441 is a wasteful number, since it uses less digits than its factorization.

142232234441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1210143.

The product of its digits is 36864, while the sum is 32.

Adding to 142232234441 its reverse (144432232241), we get a palindrome (286664466682).

It can be divided in two parts, 142232 and 234441, that added together give a palindrome (376673).

The spelling of 142232234441 in words is "one hundred forty-two billion, two hundred thirty-two million, two hundred thirty-four thousand, four hundred forty-one".

Divisors: 1 11 10781 118591 1199351 13192861 12930203131 142232234441